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| Picture of the efficient points |
In [1], a small multi-objective non-convex MINLP problem is stated:
Let's see how one could approach a problem like this.
I am a full-time consultant and provide services related to the design, implementation and deployment of mathematical programming, optimization and data-science applications. I also teach courses and workshops. Usually I cannot blog about projects I am doing, but there are many technical notes I'd like to share. Not in the least so I have an easy way to search and find them again myself. You can reach me at erwin@amsterdamoptimization.com.
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| Picture of the efficient points |
In [1], a small multi-objective non-convex MINLP problem is stated:
Let's see how one could approach a problem like this.
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| Boston custom house tower |
Assume we have an infinite collection of 3d boxes of different sizes. As an example let's use [1]:
---- 30 PARAMETER boxes available box sizes size-x size-y size-z box1 4 6 7 box2 1 2 3 box3 4 5 6 box4 10 12 32
We want to build a tower of boxes such that the base of the box on top is strictly smaller than the underlying box. The "strictly" part is essential. Otherwise, we can just repeat the same type of box ad infinitum. The interesting angle is: we can rotate the boxes. Without loss of generality, we can assume that for all boxes, after rotation, we have: the width (\(x\)) is less than the depth \((y\)). (This may require a bit of thinking). With this, any box can be placed in just three different ways.
| 3d rotations |
This post is about what sometimes is called a 2d knapsack problem. It can also be considered as a bin-packing problem. These are famously difficult problems, so let's have a look at a relatively small instance.
So, we have one 2d container of a given size. Furthermore, we have a collection of items: rectangles of a given size, with a value. The goal is to pack items in our container without overlapping each other such that the total value is maximized.
To make things concrete, let's have a look at a small data set (randomly generated):
---- 18 PARAMETER data problem data width height available value value/size k1 20.000 4.000 2.000 338.984 4.237 k2 12.000 17.000 6.000 849.246 4.163 k3 20.000 12.000 2.000 524.022 2.183 k4 16.000 7.000 9.000 263.303 2.351 k5 3.000 6.000 3.000 113.436 6.302 k6 13.000 5.000 3.000 551.072 8.478 k7 4.000 7.000 6.000 86.166 3.077 k8 6.000 18.000 8.000 755.094 6.992 k9 14.000 2.000 7.000 223.516 7.983 k10 9.000 11.000 5.000 369.560 3.733 container 30.000 20.000
In [1] the following problem is described:
This problem looks very much like the Numbrix puzzle [3]. We don't have the given cells that are provided in Numbrix, but instead, we have some cells that need to be covered by prime numbers.
The path formed by the consecutive values looks like how a rook moves on a chessboard. Which explains the title of this post (and of the original post). If we require a proper tour we need values 1 and 64 to be neighbors. Otherwise, if this is not required, I think a better term is: Hamiltonian path. I'll discuss both cases, starting with the Hamiltonian path problem.
legs = [3.3, 4.2, 5.2, 3, 2.7, 4,
5.3, 4.5, 3, 5.8, 3.3, 4.9,
3.1, 3.2, 4, 3.5, 4.9, 2.3,
3.2, 4.6, 4.5, 4, 5.3, 5.9,
2.8, 1.9, 2.1, 3, 2.5, 5.6,
1.3, 4.6, 1.5, 1.2, 4.1, 8.1]runs = [3.2, 12.3, 5.2, 2.9, 2.9, 5.5]---- 60 PARAMETER report results run1 run2 run3 run4 run5 run6 leg1 3.3 leg2 4.2 leg3 5.2 leg4 3.0 leg5 2.7 leg6 4.0 leg7 5.3 total 3.0 11.5 5.2 2.7 5.3 runLen 3.2 12.3 5.2 2.9 2.9 5.5
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| U-Haul Moving Van [link] |
This is a strange little problem [1]. We have individuals (of different categories) and regions with a given capacity. The initial set of assigned persons fits within the capacity of each region. Now a new batch of individuals arrives with their chosen zones. Unfortunately, the total demand (old + new individuals) does not fit anymore in all cases. This means we need to reallocate people. We can do this at a price (the costs are given). What is the optimal (least cost) new allocation?
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| Peter Huber, Swiss statistician |
Traditionally, regression, well-known and widely used, is based on a least-squares objective: we have quadratic costs. A disadvantage of this approach is that large deviations (say due to outliers) get a very large penalty. As a result, these outliers can affect the results dramatically.
One alternative regression method that tries to remedy this is L1- or LAD-regression (LAD=Least Absolute Deviation) [1]. Here I want to discuss a method that is somewhere in the middle between L1 regression and least-squares: Huber or M-Regression [2]. Huber regression uses a loss function that is quadratic for small deviations and linear for large ones. It is defined in a piecewise fashion. The regression can look like the following non-linear optimization problem:
| NLP Model |
|---|
| \[\begin{align} \min_{\color{darkred}\beta,\color{darkred}\varepsilon} &\sum_i \rho(\color{darkred}\varepsilon_i) \\ &\color{darkblue}y_i = \sum_j \color{darkblue}x_{i,j}\color{darkred}\beta_j +\color{darkred}\varepsilon_i \end{align} \] where \[\rho(\color{darkred}\varepsilon_i) = \begin{cases}\color{darkred}\varepsilon^2_i & \text{if $|\color{darkred}\varepsilon_i | \le \color{darkblue}k$} \\ 2\color{darkblue}k |\color{darkred}\varepsilon_i |-\color{darkblue}k^2 & \text{otherwise}\end{cases} \] |
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| Wassily Leontief in front of an IO table, credit:NYU |
GAMS allows running pieces of Python code as part of a GAMS model. Unfortunately, the interface is rather low-level and inefficient. Usually "low-level" is associated with high-performance, but in the Python world, this is not the case. Here is an example.